Answer
$c^{2}$+8c++16
Work Step by Step
In order to simplify the product $(c+4)^{2}$ we must apply the rule that states that
(a+b)=$a^{2}$+2ab+$b^{2}$, and we'll set a=c and b=4. Therefore,
$(c+4)^{2}$=$c^{2}$+2(c)(4)+$4^{2}$
=$c^{2}$+8c+16
Algebra 1
by Hall, Prentice
Published by
Prentice Hall
ISBN 10:
0133500403
ISBN 13:
978-0-13350-040-0
Chapter 8 - Polynomials and Factoring - 8-5 Factoring X(squared) + bx + c - Mixed Review - Page 505: 65
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