## Algebra 1

$c^{2}$+8c++16
In order to simplify the product $(c+4)^{2}$ we must apply the rule that states that (a+b)=$a^{2}$+2ab+$b^{2}$, and we'll set a=c and b=4. Therefore, $(c+4)^{2}$=$c^{2}$+2(c)(4)+$4^{2}$ =$c^{2}$+8c+16