Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 8 - Polynomials and Factoring - 8-5 Factoring X(squared) + bx + c - Mixed Review: 65

Answer

$c^{2}$+8c++16

Work Step by Step

In order to simplify the product $(c+4)^{2}$ we must apply the rule that states that (a+b)=$a^{2}$+2ab+$b^{2}$, and we'll set a=c and b=4. Therefore, $(c+4)^{2}$=$c^{2}$+2(c)(4)+$4^{2}$ =$c^{2}$+8c+16
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