Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 8 - Polynomials and Factoring - 8-4 Multiplying Special Cases - Practice and Problem-Solving Exercises: 58

Answer

V=$\frac{4}{3}$$\pi$($x^{2}$+6x+9)

Work Step by Step

If V=$\frac{4}{3}$$\pi$$r^{2}$ gives the volume of a sphere with radius r, to find the volume of a sphere with radius x+3 we simply plug in x+3 for r If r=x+3, then V=$\frac{4}{3}$$\pi$$(x+3)^{2}$ We then apply the rule that states that $(a+b)^{2}$=$a^{2}$+2ab+$b^{2}$ and set a=x and b=3 So V=$\frac{4}{3}$$\pi$($x^{2}$+2(x)(3)+$3^{2})$ V=$\frac{4}{3}$$\pi$($x^{2}$+6x+9)
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