## Algebra 1

The inequality is $y\lt\frac{-x}{3}-3$
$-3y-x\gt9$ We add x on both sides $-3y\gt9+x$ We divide both sides by -3 and since we divide by a negative the signs flip. $y\lt\frac{9+x}{-3}$ $y\lt\frac{-x}{3}-3$