## Algebra 1

The mistake that the student made was multiplying 3$\times4^{-1}$ Correct answer = $\frac{3}{4}$
Correct solution: f(-1) = 3 $\times 4^{-1}$ = 3 $\times \frac{1}{4^{1}}$ = 3 $\times\frac{1}{4}$ = $\frac{3}{4}$