## Algebra 1

y = $\frac{1}{4}$x - 5
To find an equation that is perpendicular to y = -4x + 5 and that passes through the point (8,-3), we first have to find the slope on the new equation. We do this by taking the negative reciprocal of the first equation. m = -4 = $\frac{1}{-4}$ = $\frac{1}{4}$ Now we substitute the slope in y=mx+b formula. y = $\frac{1}{4}$x + b Then, we substitute the point (8,-3) into this equation. (-3) = $\frac{1}{4}$(8) + b -3 = 2 + b -5 = b Now we substitute the slope and y-intercept into the equation to get the final result: y = $\frac{1}{4}$x - 5