## Algebra 1

$\frac{1}{a^{n}}$
Given : $\frac{a^{0}}{a^{n}}$ This becomes : $a^{0-n}$ , since $\frac{a^{m}}{a^{n}}=$ $a^{m-n}$ Thus, the answer is : $a^{-n}=$ $\frac{1}{a^{n}}$