Answer
$2s^6/27$
Work Step by Step
$2(3s^{-2})^{-3}$
$2*(3/s^2)^{-3}$
$2*3^{-3}/(s^2)^{-3}$
$2*(s^2)*(s^2)*(s^2)/3*3*3$
$2s^6/27$
Algebra 1
by Hall, Prentice
Published by
Prentice Hall
ISBN 10:
0133500403
ISBN 13:
978-0-13350-040-0
Chapter 7 - Exponents and Exponential Functions - 7-5 Division Properties of Exponents - Mixed Review - Page 446: 99
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