Answer
$\dfrac{1}{ w^7}$
Work Step by Step
(i) $(a^m)^n=a^{mn}$
(ii) $a^{-m} = \dfrac{1}{a^m}, a \ne 0$
Use the rules above to obtain:
$=w^{7 \cdot (-1)}
\\=w^{-7}
\\=\frac{1}{ w^7}$
Algebra 1
by Hall, Prentice
Published by
Prentice Hall
ISBN 10:
0133500403
ISBN 13:
978-0-13350-040-0
Chapter 7 - Exponents and Exponential Functions - 7-4 More Multiplication Properties of Exponents - Practice and Problem-Solving Exercises - Page 436: 14
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