Algebra 1

a) $4t^{2}$ b) 64 $in^{2}$ c) 14 in
a) radius = t diameter =2*t = 2t diameter = side of box = 2t area of box = 2t*2t = $4t^{2}$ b) radius = 4 area = $4*(4^{2})$ area = 4 * 16 = $64 in^{2}$ c) area = 196 side length = 196^{.5} = 14 inches