Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 7 - Exponents and Exponential Functions - 7-3 Multipying Powers with the Same Base - Practice and Problem-Solving Exercises: 68

Answer

$\dfrac{1}{a+b}$

Work Step by Step

(i) $x^m \cdot x^n = x^{m+n}$ (ii) $x^{-m} = \dfrac{1}{x^m}, x \ne 0$ Use rule (i) above to obtain: $=(a+b)^{2+(-3)} \\=(a+b)^{-1}$ Use rule (ii) above to obtain: $=\dfrac{1}{a+b}$
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