## Algebra 1

$4y^{5}$ + $8y^{2}$
The area of a parallelogram, Area = $base$ X $height$ Hence , Area = $4y^{2}$ X $(y^{3}+2)$ By distributive property, Area = $4y^{2}$ X $y^{3}+ 4y^{2}$ X $2$ This becomes : Area = $4y^{2+3}$ + $8y^{2}$ (since the exponents are added while multipliying with the same base) Final result : Area = $4y^{5}$ + $8y^{2}$