# Chapter 6 - Systems of Equations and Inequalities - Get Ready - Page 357: 13

a) height = $2x-1$ b) area = $\frac{1}{2}x(2x-1)$ c) 248 cm$^2$

#### Work Step by Step

a) To write an expression for one less than twice the length, you multiply the length by 2 and subtract 1 from the product. b) The area of a triangle is $\frac{1}{2}$ the length times the height. c) $\frac{1}{2}x(2x-1)\longrightarrow$ substitute 16 for x and solve $\ \ \$=$\frac{1}{2}(16)(2\times16-1)$ $\ \ \$=$8(31)$ $\ \ \$=$248$

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