Algebra 1

One line goes through $(-2, 0)$ and $(0,-2)$. The other line goes through $(2,3)$ and $(-1, -1)$ $m=(0--2)/(-2-0)$ $m = 2/-2 = -1$ $y=mx+b$ $-2 = -1*0+b$ $-2 = b$ $y=-x-2$ $m=(3--1)/(2--1)$ $m=4/3$ $y=mx+b$ $3=4/3*2+b$ $3 = 8/3+b$ $9/3 = 8/3 +b$ $1/3=b$ $y=4/3x+1/3$ $-x-2 = 4/3x+1/3$ $3*(-x-2 = 4/3x+1/3)$ $-3x-6 = 4x+1$ $-3x-6+3x+6 = 4x+1+3x+6$ $0 = 7x+7$ $-7 = 7x$ $-7/7 = 7x/7$ $-1 = x$ $y=-x-2$ $y=-(-1)-2$ $y=1-2$ $y=-1$ $(-1, -1)$ is the intersection of the two lines.