## Algebra 1

$y\geq3/2*x-3$
(2,0) and (0, -3) $m = (0--3)/(2-0)$ $m = 3/2$ $y= mx+b$ $0 = 3/2*2+b$ $0 = 3+b$ $0-3 = 3+b-3$ $-3 = b$ $y=3/2*x-3$ Since (0,0) is part of the solution set, we use the $\geq$ sign. $y\geq3/2*x-3$