## Algebra 1

Published by Prentice Hall

# Chapter 6 - Systems of Equations and Inequalities - 6-3 Solving Systems Using Elimination - Lesson Check: 3

#### Answer

$(\frac{7}{25},-\frac{2}{25})$

#### Work Step by Step

Multiply the first equation by 3. Multiply the second equation by 2. Add the equations to eliminate y. $3x-2y=1\ \ \ \$multiply by 3$\ \ \ \ \ \ 9x-6y=3$ $8x+3y=2\ \ \ \$multiply by 2$\ \ \ \ \underline{16x+6y=4}$ $\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 25x\ \ \ \ \ \ \ \ \ =7$ Solve for x. $25x=7$ $25x\div25=7\div25$ $x=\frac{7}{25}$ Substitute $\frac{7}{25}$ for x in either equation to solve for y. $8x+3y=2$ $8(\frac{7}{25})+3y=2$ $2\frac{6}{25}+3y-2\frac{6}{25}=2-2\frac{6}{25}$ $3y=-\frac{6}{25}$ $3y\div3=-\frac{6}{25}\div3$ $y=-\frac{2}{25}$

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