Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 6 - Systems of Equations and Inequalities - 6-1 Solving Systems by Graphing - Standardized Test Prep - Page 365: 43


Solution to the system (2,-7)

Work Step by Step

Given: Equation one:2x+3y=-17 Equation two: 3x+2y=-8 In equation, we can use elimination method to find y. Subtract 2x from both sides then divide both sides by 3. => 3y=-2x-17 => y=$\frac{-2}{3}$x-$\frac{17}{3}$ Substitute y into second equation. We have: 3x+2($\frac{-2}{3}$-$\frac{17}{3}$)=-8. Distribute 2: 3x-$\frac{4}{3}$x-$\frac{34}{3}$=-8. Combine like terms and simplify: $\frac{5}{3}$x=$\frac{10}{3}$=> x = 2 When x=2, 2(2)+3y=-17=>4+3y=-17=>3y=-21=>y=-7 Point of intersection: (2,-7)
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