## Algebra 1

$x+2y = 6$, Standard form chosen since both intercepts were given
(6,0) and (0,3) are the intercepts $m = (3-0)/(0-6)$ $m=3/-6 = -1/2$ $y = -1/2x+b$ $3 = -1/2*0+b$ $3 = 0 + b$ $3 = b$ $y=-1/2*x+3$ $y+1/2*x=-1/2*x+3+1/2*x$ $1/2*x+y = 3$ $2(1/2*x+y)= 2*3$ $x+2y = 6$