## Algebra 1

$y = \frac{-3}{2}x+0$ (or $y = \frac{-3}{2}x$)
(0,0) and (2,-3) $m = (0--3)/(0-2) = 3/-2 =-3/2$ $y= mx+b$ $0 = (-3/2) * 0 + b$ $0 = 0 + b$ $0 = b$