## Algebra 1

$y=-9$
Line $p$ goes through $(5,-2)$ and has $m=0$ $y=mx+b$ $-2 = 0*5+b$ $-2 = 0+b$ $-2 = b$ $y=-2$ Line $q$ is parallel to line $p$, so the equation for line $q$ will also be of the form $y=b$. $(-13, -9)$ $y=mx+b$ $-9 = -13*0+b$ $-9 = 0+b$ $-9 = b$ $y=-9$