## Algebra 1

D) $w=\frac{P}{2}-ℓ$
To solve for the width, $w$ needs to be isolated on its own side of the equation. $P=2(ℓ+w)$ $P\div2=(2(ℓ+w))\div2$ $\frac{P}{2}=ℓ+w$ $\frac{P}{2}-ℓ=w$ This means that the answer is D, $w=\frac{P}{2}-ℓ$.