Algebra 1

$y-1=\frac{1}{3}(x-5)$
The point-slope form of an equation of a non-vertical line with slope $m$ and through point $(x_1,y_1)$ is $y-y_1=m(x-x_1)$. We plug in $5$ for $x_1$, $1$ for $y_1$, and $\frac{1}{3}$ for $m$ to get the equation: $y-1=\frac{1}{3}(x-5)$