## Algebra 1

$2x-5y = 0$ and $y+3 = 5/2*x$ $2x-5y = 0$ $2x-5y +5y = 0+5y$ $2x = 5y$ $2x/5 = 5y/5$ $2/5*x = y$ $2/5*x = y$ has $m=2/5$ $y+3 = 5/2*x$ $y+3-3 = 5/2*x-3$ $y = 5/2*x-3$ $y = 5/2*x-3$ has $m=5/2$ $5/2 \ne 2/5$, and $5/2*2/5 = 10/10 = 1$ $1 \ne -1$, so the lines are neither parallel or perpendicular