## Algebra 1

$y=x-5$
(3, -2) and (6,1) given $m = (1--2)/(6-3)$ $m = 3/3 = 1$ $y = mx+b$ $1 = 6 + b$ $1-6 = 6 + b - 6$ $-5 = b$ $y=x-5$