## Algebra 1

$y = -2/3*x +10/3$
Parallel to $2x+3y =9$ and through (-1, 4) $2x+3y = 9$ $2x+3y -3y-9 = 9 - 3y - 9$ $2x-9 = -3y$ $-1/3*(2x-9) = -3y/-3$ $-2/3*x + 3 = y$ $y = -2/3*x +3$ The parallel line would have the same slope (-2/3). $4 = -2/3*(-1)+b$ $4 = 2/3 +b$ $4-2/3 = 2/3 + b - 2/3$ $10/3 = b$ $y = -2/3*x +10/3$