## Algebra 1

slope of AB: $m=(3--2)/(-3--1)$ $m = 5/-2$ $m = -5/2$ slope of CD: $m =(5-0)/(2-4)$ $m = 5/-2$ $m= -5/2$ slope of BC: $m=(0--2)/(4--1)$ $m= 2/5$ slope of AD: $m = (5-3)/(2--3)$ $m = 2/5$ AB is perpendicular to BC and AD (-5/2 * 2/5 = 1) CD is perpendicular to BC and AD (-5/2 * 2/5 = 1) AB and CD are parallel BC and AD are parallel opposite sides are parallel and adjacent sides are perpendicular, thus the shape is a rectangle