## Algebra 1

$x-3y = -6$ Let $x = 0$ $x-3y = -6$ $0-3y = -6$ $-3y = -6$ $-3y/-3 = -6/-3$ $y= 2$ Let $y = 0$ $x - 3y = -6$ $x - 3*0 = -6$ $x - 0 = -6$ $x = -6$ The given points are (0,2) and (-6,0)