## Algebra 1

y-4=3(x+1) is not an equation of a line through (-2, 1) because a point is written in the form (x, y), so if the point (-2, 1) was on the graph of y-4=3(x+1), then when you plugged in -2 for x and 1 for y the equation would be equalivalent 1-3=3(-2+1) -2=3(-1) -2$\ne$-3 Since -2 is not equal to -3, the point (-2, 1) doesn't exist on the graph of the equation y-4=3(x+1)