## Algebra 1

Yes it is an arithmetic sequence, and the common difference is -$\frac{1}{6}$
The difference between consecutive terms is constant in an arithmetic sequence. The sequence: $\frac{1}{2}, \frac{1}{3}, \frac{1}{6}, 0$ Finding the pattern: Difference between 1st and 2nd term: 2nd term-1st term=Difference $\frac{1}{3}-\frac{1}{2}$= -$\frac{1}{6}$ Difference between 2nd and 3rd term: 3rd term-2nd term=Difference $\frac{1}{6}-\frac{1}{3}$= -$\frac{1}{6}$ Difference between 3rd and 4th term: 4th term-3rd term=Difference 0-$\frac{1}{6}$= -$\frac{1}{6}$ The common difference is -$\frac{1}{6}$ and it is constant thus this is an arithmetic sequence.