Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 4 - An Introduction to Functions - 4-2 Patterns and Linear Functions - Practice and Problem-Solving Exercises - Page 243: 10

Answer

The relation is a linear function. For every increase in the x-value, the y-value decreases by 11 units. Equation: y=-11x+43
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Work Step by Step

The relationship is a linear function because the graph decreases by 11 units every time for every x-value Equation: Slope: $\frac{(y_{2}-y_{1})}{(x_{2}-x_{1})}$ $\frac{(32-43)}{(1-0)}$ $\frac{-11}{1}$ slope=-11 y-int: y=-11x+b (substitute any x & y value from the table) 21=-11(2)+b 21=-22+b +22 +22 43=b Equation: y=-11x+43
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