## Algebra 1

The relationship is a linear function because the graph decreases by 11 units every time for every x-value Equation: Slope: $\frac{(y_{2}-y_{1})}{(x_{2}-x_{1})}$ $\frac{(32-43)}{(1-0)}$ $\frac{-11}{1}$ slope=-11 y-int: y=-11x+b (substitute any x & y value from the table) 21=-11(2)+b 21=-22+b +22 +22 43=b Equation: y=-11x+43