## Algebra 1

Published by Prentice Hall

# Chapter 3 - Solving Inequalities - Get Ready - Page 161: 27

#### Answer

$y=\frac{1}{2}$

#### Work Step by Step

$\frac{1}{3}+\frac{4y}{6}=\frac{2}{3}\longrightarrow$ convert all fractions to a common denominator $\frac{1}{3}+\frac{4y\div2}{6\div2}=\frac{2}{3}\longrightarrow$ simplify $\frac{1}{3}+\frac{2y}{3}=\frac{2}{3}\longrightarrow$ subtract $\frac{1}{3}$ from each side $\frac{1}{3}+\frac{2y}{3}-\frac{1}{3}=\frac{2}{3}-\frac{1}{3}\longrightarrow$ subtract $\frac{2y}{3}=\frac{1}{3}\longrightarrow$ multiply both sides by $\frac{3}{2}$ $\frac{2y}{3}\times\frac{3}{2}=\frac{1}{3}\times\frac{3}{2}\longrightarrow$ multiply $y=\frac{3}{6}\longrightarrow$ reduce $y=\frac{3\div3}{6\div3}\longrightarrow$ simplify $y=\frac{1}{2}$ When we plug our solution back into the equation, we find that each side of the equation is equal, making our answer correct.

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.