## Algebra 1

The problem tells us that in the spring we could serve 43 mph and now after summer, our service speed has increased by 12 %. So if 43 mph is 100% then we can say that now we are 112% of our original speed since the speed increased by 12%. Now we can just take 112% of 43 mph. First we covert 112% into a decimal by dividing by 100. 112$\div$100=1.12. No we just multiply 1.12 with 43 which equals 48.16. If we round it, we get 48 mph. So our answer is G: 48 mi/h