## Algebra 1

$c= 16/3, -6$
$abs (3c+1) -4 =13$ $abs (3c+1) -4+4 =13+4$ $abs(3c+1) = 17$ $3c+1 = 17$ and $3c+1=-17$ $3c+1=17$ $3c = 16$ $3c/3= 16/3$ $c=16/3$ $3c+1=-17$ $3c+1-1=-17-1$ $3c = -18$ $3c/3=-18/3$ $c=-6$ Let $c=16/3$: $abs(3c+1)-4=13$ $abs(3*16/3+1)-4=13$ $abs(16+1)-4=13$ $abs(17)-4=13$ $17-4 = 13$ is a true statement Let $c=-6$: $abs(3c+1)-4=13$ $abs(3*-6+1)-4=13$ $abs(-18+1)-4=13$ $abs(-17)-4=13$ $17-4=13$ is a true statement