#### Answer

B

#### Work Step by Step

$X=\{1, 2, 3, 4, 6, 12\}$
$Y=\{1, 2, 4, 8, 16\}$
.
$X\cap Y$ contains all the elements the sets have in common
A is not correct because it is the empty set, and there are common elements.
B is correct because 1, 2 and 4 are in both X and Y.
C is not correct because 0 is not in either X or Y.
D is not correct because it includes multiple elements that are not in both X and Y, such as 12 and 16.