## Algebra 1

The two inequalities $abs(x-1) \geq 2$ and $abs(x-1)\leq 2$ have ranges of possible values. However, the inequality $abs(x-1) = 2$ has two possible values. $abs(x-1) = 2$, so $x=3$ and $x = -1$
An inequality in the form $abs(A)\leq b$ is solved by solving the inequality $-b \leq A \leq b$. An inequality in the form $abs(A) \geq b$ is solved by solving the compound inequality $A \leq -b$ or $A \geq b$.