## Algebra 1

$z\gt2$ or $z\lt-1$
$5z-3\gt7\longrightarrow$ add 3 to each side $5z-3+3\gt7+3\longrightarrow$ add $5z\gt10\longrightarrow$ divide each side by 5 $5z\div5\gt10\div5\longrightarrow$ divide $z\gt2$ or $4z-6\lt-10$ add 6 to each side $4z-6+6\lt-10+6\longrightarrow$ add $4z\lt-4\longrightarrow$ divide each side by 4 $4z\div4\lt-4\div4\longrightarrow$ divide $z\lt-1$ Since 2 and -1 are not in the solution sets, the endpoint of the graph is an open circle.