## Algebra 1

a) I would expect the solution to be of the form $y < c$. b) 1.75 = y (estimate) c) $y < \frac{22}{13}$
a) Since the table value changed from true to false for a value of 2, 2 would be deemed not a number in the solution set. (Thus, y>2 would not work.) b) This is just an estimate. Since the inequality moves from true to false with a value of 2, I would estimate the value where the inequality moves from true to false is halfway between 1.5 and 2. c) The estimate was a bit too high, as y < 1.692. $7y + 2 < 6 (4-y)$ $7y + 2 < 24 - 6y$ $7y + 2 (-2) < 24 (-2) - 6y$ $7y < 22 - 6y$ $7y (+6y)< 22 - 6y (+6y)$ $13y < 22$ $y < \frac{22}{13}$