## Algebra 1

$-5r+6\leq-5(r+2)\longrightarrow$ multiply using the distributive property $-5r+6\leq-5r-10\longrightarrow$ add 5r to each side $-5r+6+5r\leq-5r-10+5r\longrightarrow$ add $6\leq-10$ Since 6 is not less than or equal to -10, there is no solution.