Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 3 - Solving Inequalities - 3-3 Solving Inequalities Using Multiplication or Division - Practice and Problem-Solving Exercises - Page 182: 49

Answer

The speed would have to be greater than 0.08 mi/min

Work Step by Step

We know distance = speed*time To be at the park at 25 max, the equation is distance/speed\leq25. Since the distance is 2 miles, we can make an equation 2/25\leqspeed. This equals 0.08\leqspeed. So he has to run at a speed of 0.08 miles/min or faster.
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