## Algebra 1

The inequality would add up a variable, $x$, and the pre-added weights on the lift, 124 and 32. They would have to be equal to or less than 680. That would create: $x+124+32\leq 680$ Then, simply solve it like an equation. $x+156\leq 680$ $(x+156)-156\leq (680)-156$ $x\leq 524$ This means that with what's already on the chairlift, it can take another 524 lbs. To check it, insert 524 into the inequality. $524+124+32\leq 680$ $680\leq 680$✔ Below is how to graph it on the number line. All values within the arrow could be added to the chairlift.