## Algebra 1

$\frac{23}{29}$
$\frac{2^3\times4-(-3)^2}{(-3)^2+4\times5}$ simplify the exponents =$\frac{8\times4-9}{9+4\times5}$ simplify using multiplication =$\frac{32-9}{9+20}$ simplify using addition =$\frac{23}{29}$ There are implied parentheses around the numerator and around the denominator.