Answer
$\frac{23}{29}$
Work Step by Step
$\frac{2^3\times4-(-3)^2}{(-3)^2+4\times5}$ simplify the exponents
=$\frac{8\times4-9}{9+4\times5}$ simplify using multiplication
=$\frac{32-9}{9+20}$ simplify using addition
=$\frac{23}{29}$
There are implied parentheses around the numerator and around the denominator.
