#### Answer

$P=26.8in$
$A=52.3in^2$

#### Work Step by Step

The perimeter of the figure $P$ can be found by adding up all of the exterior side lengths.
The perimeter or circumference of the half circle is found with the formula $P_{h}=$$\pi$$r$.
Substitute the given value for $r$ and use $3.14$ for $\pi$ in the formula above.
$P_{h}$=$(3.14)(3)$
$P_{h}$=$9.42$
Since there are 2 half circles in the figure, simply multiply the answer above by 2:
$9.42$$\times$$2$=$18.84$
The exterior side lengths of the rectangle are given as $4$ and $4$ which add up to $8$.
Therefore, $P=18.84+8=26.84$ which rounds to $26.8$
The area of the figure $A$ is the sum of the area of the first half circle $A_{h_1}$, the area of the second half circle $A_{h_2}$, and the area of the rectangle $A_{r}$.
Use $3.14$ for $\pi$
$A_{h_1}$=$\frac{1}{2}$$\pi$$r^2$
$A_{h_1}$=$\frac{1}{2}$$(3.14)(3^2)$
$A_{h_1}$=$14.13$
$A_{h_2}$=$\frac{1}{2}$$\pi$$r^2$
$A_{h_2}$=$\frac{1}{2}$$(3.14)(3^2)$
$A_{h_2}$=$14.13$
$A_{r}$=$lw$
$A_{r}$=$4(6)$
$A_{r}$=$24$
Add up all of the solved areas to find $A$: $A=14.13+14.13+24=52.26$ which rounds to $52.3$