Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 2 - Solving Equations - Chapter Review - 2-5 Literal Equations and Formulas - Page 154: 34


Width = 40 cm

Work Step by Step

You can use properties of equality to solve a literal equation for one variable in terms of others. In this question, you need to find the width of a rectangle. First, find the formula of the area of a rectangle. The formula for the area of a rectangle is: Area = length $\times$ width We are given that the rectangle has a length of 5.5 cm and an area of 220$cm^{2}$. Next, plug in the information given into the formula: 220$cm^{2}$ = 5.5 cm $\times$ width To find the width, solve the equation. (You can make width the variable x.) 220$cm^{2}$ = 5.5 cm $\times$ x Divide both sides by 5.5 cm. $\frac{220cm^{2}}{5.5 cm}$ = $\frac{5.5 cm \times x }{5.5 cm}$ Simplify to get: 40 cm = x
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