## Algebra 1

$n=(2m-3)/(-6)$
The literal equation made an error when moving the "+3" to the opposite side of the equation. Rather than properly subtracting 3 from both sides of the equation, the "+3" was simply moved from one side of the equation to the other. The correct process would be as such: $2m=-6n+3$ $2m-3=-6n+3-3$ $2m-3=-6n$ $(2m-3)/(-6)=-6n/(-6)$ $(2m-3)/(-6)= n$ Or $n=(2m-3)/(-6)$