Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 2 - Solving Equations - 2-5 Literal Equations and Formulas - Lesson Check: 4

Answer

$F=\frac{9}{5}C+32$

Work Step by Step

We are trying to isolate the variable $F$ in $C=\frac{5}{9}(F-32)$. First, we multiply both sides by $\frac{9}{5}$, the reciprocal of $\frac{5}{9}$: $\frac{9}{5}C=F-32$ Then, we add $32$ to both sides to isolate the $F$: $F=\frac{9}{5}C+32$
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