Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 2 - Solving Equations - 2-4 Solving Equations with Variables on Both Sides - Practice and Problem-Solving Exercises: 21

Answer

q = 25

Work Step by Step

3(q-5) = 2(q+5) Use the distributive property: 3(q) - 3(5) = 2(q) + 2(5) Simplify: 3q - 15 = 2q + 10 To get the variable (q) on one side of the equation, subtract 2q from both sides of the equation. 3q - 15 - 2q = 2q + 10 - 2q Simplify to get: 1q - 15 = 10 Add 15 to both sides of the equation. 1q - 15 + 15 = 10 + 15 1q = 25 Divide both sides by 1: $\frac{1q}{1}$ = $\frac{25}{1}$ q = 25 Check: To check whether 25 is the correct answer, replace q with 25 in the original equation and solve. 3(q-5) = 2(q+5) 3(25-5) = 2(25+5) 3(20) = 2(30) 60 = 60
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