#### Answer

a) 21% increase
b) 21% increase
c) My prediction is that the increase would be a 21% increase. 21% increase for the square.

#### Work Step by Step

a) original is 4x4, new is 10% larger on each side
original area: $4*4 = 16$
new area: $4*1.1*4*1.1 = 4.4*4.4 = 19.36$
$(19.36-16)/16 = 3.36/16 = .21$ = 21%
b) original is 6x6, new is 10% larger on each side
original area: $6*6 = 36$
new area: $6*1.1*6*1.1 = 6.6 * 6.6 = 43.56$
$(43.56-36)/36 = 7.56/36 = .21 =$ 21%
c) original is 8x8, new is 10% larger on each side
original area: $8*8 = 64$
new area: $8*1.1*8*1.1 = 77.44$
$(77.44-64)/64 = 13.44/64 = .21 =$ 21%
Let $x$ be the original side length of a square, and let us increase the side lengths by 10%. (The new side length is $1.1*x$, or $1.1x$.) The original area of the square would be $x^{2}$, and the new area would be $(1.1*x)^{2}$, or $1.21x^{2}$. Change in area: $(1.21x^{2} - x^{2})/x^{2} = .21x^{2}/x^{2} = .21$ = 21%