Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 12 - Data Analysis and Probability - Chapter Review - 12-6 Permutations and Combinations - Page 777: 28



Work Step by Step

Use the formula of combination: $_{n}$C$_{r}$=$\frac{n!}{r!(n-r)!}$. Plug in 8 for N and 2 for R: $_{n}$C$_{r}$=$\frac{n!}{r!(n-r)!}$ $_{8}$C$_{2}$=$\frac{8!}{2!(8-2)!}$ -simplify like terms- $_{8}$C$_{2}$=$\frac{8!}{2! (6!)}$ -write using factorial- $_{8}$C$_{2}$=$\frac{8*7*6*5*4*3*2*1}{(2*1)(6*5*4*3*2*1)}$ -simplify- $_{8}$C$_{2}$=28
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.