# Chapter 12 - Data Analysis and Probability - 12-6 Permutations and Combinations - Practice and Problem-Solving Exercises - Page 756: 60

8

#### Work Step by Step

$3C3 + 3C2 + 3C1 + 3C0$ $3!/(3-3)!3! + 3!/(3-2)!2! +3!/(3-1)!1! + 3!/(3-0)!0!$ $6/0!3! + 6/1!2! + 6/2!1! + 6/3!*1$ $6/6*1 + 6/2 + 6/2 + 6/6*1$ $1 + 3 + 3 + 1 = 8$

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