Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 12 - Data Analysis and Probability - 12-6 Permutations and Combinations - Practice and Problem-Solving Exercises - Page 754: 28

Answer

5

Work Step by Step

Use the formula of combination: $_{n}$C$_{r}$=$\frac{n!}{r!(n-r)!}$. Plug in 5 for N and 4 for R: $_{n}$C$_{r}$=$\frac{n!}{r!(n-r)!}$ $_{5}$C$_{4}$=$\frac{5!}{4!(5-4)!}$ -simplify like terms- $_{5}$C$_{4}$=$\frac{5!}{4! (1!)}$ -write using factorial- $_{5}$C$_{4}$=$\frac{5*4*3*2*1}{(4*3*2*1)(1)}$ -simplify- $_{5}$C$_{4}$=5
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