## Algebra 1

First you separate 2 and \sqrt 108. $\sqrt108$ = $\sqrt 36\times \sqrt3.$ $\sqrt 36$ = 6 and $\sqrt 3$ = $\sqrt 3.$ Since $\sqrt 108$ = $6\sqrt 3$, multiply by 2 2$\times$6 $\sqrt 3$ 12$\sqrt 3$ Answer is A